How will the waveform differ if we use a real capacitor and diode if input is a sin wave |
by SrvSny
July 06, 2020 |
You could draw the circuit, isn't it? If there is a single diode in serial to the cap, that will more or less slowly charge the cap to Vsource - Vthreshold since when the voltage reverse bias the diode, no current would flow and the cap won't be able to discharge itself. If the single diode is in parallel to the cap, the cap will charge at Vthreshold ( typically 0.7 volt for a discrete silicium diode ) when the diode is forward biased, and to -Vsource when the diode is reversed biased. Unless that diode is a Zener diode, that is (as the name "clamper" may be a hint). |
by vanderghast
July 07, 2020 |
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