Stepper Motor Enable line

Hi there

I am using DRV8834 IC driver to run the 5v stepper motor. I've managed to run the 5v stepper motor using DRV8834 IC. But I've found we need 3 pins (Step, Direction and enable) to enable the device.

The requirement is to reduce the pins to 2 (only for step and direction). If I don't use the enable pin then the driver and motor consume tiny power. Is there any idea you can help me with to use any MOSFET/any other idea/pulse stretcher to control the power consumption without using the enable pin? Please let me know if you guys got an idea. Your help is much appreciated.

Thanks in advance.

by dhinesh.ganesan
October 19, 2017

2 Answers

Answer by mikerogerswsm

I would try using the step signal direct to 'enable' and delayed to 'step'. A suitable delay is a series R, C to ground, followed by a CMOS schmitt trigger. A more rigorous solution is to delay both signals but add diodes across the R so one has delayed 'up' and one a delayed 'down'. This would ensure the 'enable' is longer than each 'step'.

+1 vote
by mikerogerswsm
October 19, 2017

Answer by dhinesh.ganesan

Thanks for your help! and Let me check.

+1 vote
by dhinesh.ganesan
October 19, 2017

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