Hi there I am using DRV8834 IC driver to run the 5v stepper motor. I've managed to run the 5v stepper motor using DRV8834 IC. But I've found we need 3 pins (Step, Direction and enable) to enable the device. The requirement is to reduce the pins to 2 (only for step and direction). If I don't use the enable pin then the driver and motor consume tiny power. Is there any idea you can help me with to use any MOSFET/any other idea/pulse stretcher to control the power consumption without using the enable pin? Please let me know if you guys got an idea. Your help is much appreciated. Thanks in advance. |
by dhinesh.ganesan
October 19, 2017 |
I would try using the step signal direct to 'enable' and delayed to 'step'. A suitable delay is a series R, C to ground, followed by a CMOS schmitt trigger. A more rigorous solution is to delay both signals but add diodes across the R so one has delayed 'up' and one a delayed 'down'. This would ensure the 'enable' is longer than each 'step'. |
+1 vote by mikerogerswsm October 19, 2017 |
Thanks for your help! and Let me check. |
+1 vote by dhinesh.ganesan October 19, 2017 |
You must log in or create an account (free!) to answer a question.
Anyone can ask a question.
Did you already search (see above) to see if a similar question has already been answered? If you can't find the answer, you may ask a question.
CircuitLab's Q&A site is a FREE questions and answers forum for electronics and electrical engineering students, hobbyists, and professionals.
We encourage you to use our built-in schematic & simulation software to add more detail to your questions and answers.
Acceptable Questions:
Unacceptable Questions:
Please respect that there are both seasoned experts and total newbies here: please be nice, be constructive, and be specific!
CircuitLab is an in-browser schematic capture and circuit simulation software tool to help you rapidly design and analyze analog and digital electronics systems.