just a hard question in my college, I have a link in here, if you do not want to answer, we will solve it ourselves :D but thanks for clicking in for taking a view, inside the website I do not know how to calculate the answer of to 1-6
5 days, 9 hours ago
Nice question! At the start of limiting Vx=3V and Vin=3.7V, and in limiting the excess input is potted down by R3 into R1//R2. Max excess is 5V-3.7V=1.3V potted down by 10k into about 1k, or about 0.13V. Just within spec. You'll have to be a bit more rigorous, but that should set you on track. Hope I helped without spoiling the fun. mike
1 day, 23 hours ago
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