Inductor SOLVED

Good day Team, Question: A current of 4A flows in an inductor, and the energy stored by the inductor in joules is 12J, what will be the value of the inductor in henry?

by S.Tech
February 17, 2018

1 Answer

Answer by mrobbins

Energy stored in the magnetic field of an inductor is

$$E = \frac {1} {2} L I^2$$

So we can solve for $L$:

$$L = \frac {2 E} {I^2}$$

or with your numbers:

$$L = \frac {2 (12\ \text{J})} {(4\ \text{A})^2}= 1.5\ \text{H}$$

ACCEPTED +1 vote
by mrobbins
February 17, 2018

Your Answer

You must log in or create an account (free!) to answer a question.

Log in Create an account

Go Ad-Free. Activate your CircuitLab membership. No more ads. Save unlimited circuits. Run unlimited simulations.

Search Questions & Answers

Ask a Question

Anyone can ask a question.

Did you already search (see above) to see if a similar question has already been answered? If you can't find the answer, you may ask a question.

About This Site

CircuitLab's Q&A site is a FREE questions and answers forum for electronics and electrical engineering students, hobbyists, and professionals.

We encourage you to use our built-in schematic & simulation software to add more detail to your questions and answers.

Acceptable Questions:

  • Concept or theory questions
  • Practical engineering questions
  • “Homework” questions
  • Software/hardware intersection
  • Best practices
  • Design choices & component selection
  • Troubleshooting

Unacceptable Questions:

  • Non-English language content
  • Non-question discussion
  • Non-electronics questions
  • Vendor-specific topics
  • Pure software questions
  • CircuitLab software support

Please respect that there are both seasoned experts and total newbies here: please be nice, be constructive, and be specific!

About CircuitLab

CircuitLab is an in-browser schematic capture and circuit simulation software tool to help you rapidly design and analyze analog and digital electronics systems.