## Zener Diode Characteristic Curve

 Take note of the axis (which one is horizontal and which one is vertical). Haven't found the way to exchange them. I added a ground to specify where is the reference (a voltage is always a difference about TWO points. When a single point is given, that implies that the second point is the referenced ground) in order to simplify the graph. Or, if you prefer, the voltage across the diode is the difference of potential between, first, the current source and the diode, and, second, the diode and the resistor. When the latter is zero, that simplify the equation to be used to get the voltage ACROSS the diode. +1 vote by vanderghast October 09, 2020 I like this concept. Here's my simplification: Resistor in series with an ideal current source is basically irrelevant, so I've removed R1. Then I flipped around the elements a bit, and extended the DC Sweep to include both positive and negative currents: Take a look at this simulation. I think you'll find that the two "plateau" areas on the I-V curve are where you expect: one around +0.7V, and one around -5.1V (for this particular Zener part number). by mrobbins October 09, 2020 Add comment... Please sign in or create an account to comment.

 Thanks to both of you. I'll look closely at your ideas this weekend and I might suggest a description of both options to my students without actually giving them a circuit. By now they should be able to put together a circuit and play from someone's description. I'm excited to try this!! C. Strong UAH +1 vote by strongc October 09, 2020 Add comment... Please sign in or create an account to comment.

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