|
I'm trying to do something a little tricky and am looking for some guidance. I have a 12VDC light bulb that I will be screwing into a light fixture that is wire to a 12VDC power supply. I would like to have a relay output to trigger when the bulb is screwed in and the circuit is completed. The output should turn off when the bulb is unscrewed. Any ideas? |
September 24, 2018 |
|
Put in a series resistor that drops say 100mV at the normal lamp current at the ground end, then use a comparator to detect this and drive your relay. In theory a relay could be used directly, but it has to work on the lamp current without dropping too many volts. |
September 27, 2018 |
|
Thanks Mike. Do you think something like this will work? https://www.adafruit.com/product/904 |
September 27, 2018 |
|
Yes, no reason why not, though it does far more than you need. |
September 27, 2018 |
No answers yet. Contribute your answer below!
You must log in or create an account (free!) to answer a question.
Anyone can ask a question.
Did you already search (see above) to see if a similar question has already been answered? If you can't find the answer, you may ask a question.
CircuitLab's Q&A site is a FREE questions and answers forum for electronics and electrical engineering students, hobbyists, and professionals.
We encourage you to use our built-in schematic & simulation software to add more detail to your questions and answers.
Acceptable Questions:
Unacceptable Questions:
Please respect that there are both seasoned experts and total newbies here: please be nice, be constructive, and be specific!
CircuitLab is an in-browser schematic capture and circuit simulation software tool to help you rapidly design and analyze analog and digital electronics systems.