555 frequency driver circuit

Components Required: 555 Timer IC 4017 counter IC Bread Board Resistor 330, 220, 10K, 47k ohm 50k POT LEDs 4.7uF Capacitor 10nF Capacitor SPDT switch Jumper wire 9V battery or supply Voltage Regulator LM7805 All components are provided in: www.hqew.net Working Explanation: Working of this Frequency Divider Circuit is simple. Here we have made a 555 based astable multivibrator for the input signal and we are controlling the frequency of the signal by using a potentiometer.

When we connect supply to circuit then Astable Multivibrator generates a frequency which can be easily seen by the blinking LED D1. This signal is applied to the clock input of counter IC 4017 as a clock pulse. Frequency-Divider-Circuit-using-555-Timer-and-CD4017_0.jpg In case of the frequency divided by 2 (f/2), we have applied the Q2 output to reset pin (15) of counter IC by using SPDT switch so that the counter IC reset itself and starts from the beginning (Q0). Means for first clock pulse output Q1 will be high and for second clock pulse output Q2 will be high which resets the IC and makes the output Q0 high. For third clock pulse output Q1 will be high again and LED will glow. So for every two input clock pulse, LED D2 will be high once, that how it divides the frequency by 2. So the final output of the counter IC will be: In case of frequency divided by 4 (f/4), we have applied the Q4 output to reset pin (15) of counter IC by using SPDT switch so IC 4017 will be reset in the fourth pulse, hence LED D2 will glow once during four pulses. Initially, Q0 will be high that is the default state of IC, then for first clock pulse output Q1 will be high and LED D2 will glow. For second and third clock pulses, output Q2 and Q3 will be high respectively. Now in fourth pulse Q4 gets high and resets the IC as it is connected to reset Pin 15 of IC 4017 (Q0 high). For fifth clock pulse output Q1 will be high again and LED will glow. So here, for every four input clock pulses, LED D2 will be high once, that how it divides the frequency by 4 (f/4).

by circuit12
4 days, 2 hours ago

Well, that's all very interesting. Now, what is your question?

by mikerogerswsm
3 days, 19 hours ago
Add comment...

Please sign in or create an account to comment.


No Answers

No answers yet. Contribute your answer below!


Your Answer

You must log in or create an account (free!) to answer a question.

Log in Create an account


Go Ad-Free. Activate your CircuitLab membership. No more ads. Save unlimited circuits. Run unlimited simulations.

Search Questions & Answers


Ask a Question

Anyone can ask a question.

Did you already search (see above) to see if a similar question has already been answered? If you can't find the answer, you may ask a question.


About This Site

CircuitLab's Q&A site is a FREE questions and answers forum for electronics and electrical engineering students, hobbyists, and professionals.

We encourage you to use our built-in schematic & simulation software to add more detail to your questions and answers.

Acceptable Questions:

  • Concept or theory questions
  • Practical engineering questions
  • “Homework” questions
  • Software/hardware intersection
  • Best practices
  • Design choices & component selection
  • Troubleshooting

Unacceptable Questions:

  • Non-English language content
  • Non-question discussion
  • Non-electronics questions
  • Vendor-specific topics
  • Pure software questions
  • CircuitLab software support

Please respect that there are both seasoned experts and total newbies here: please be nice, be constructive, and be specific!

About CircuitLab

CircuitLab is an in-browser schematic capture and circuit simulation software tool to help you rapidly design and analyze analog and digital electronics systems.