Here in this configurationas you see the emitter is connected to a potential of 9V constantly. The base gets a potential of roughly 6-8 V and the collector gets a 27 V potential. So how does the transistor work here provided that 9 V is always there at the emitter and what is the use of the diode there. |
by aman_dixit
March 20, 2019 |
9.8 turns on the transistor energizing your collector load. diode makes sure bias voltage goes thru the bpt instead of battery. |
+1 vote by mu34tant March 30, 2019 |
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