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Hi,

I need to draw with circuit lab these two generator:

1) Voltage 2VCOS(wt)

2) Currente 2 SQR2 (wt + PI / 4)

Where w = 5*10^5 rad / s

Someone can help me?

Are you sure about (2):

Currente 2 SQR2 (wt + PI / 4)

?

That is a not a sinusoidal function of time. The current is proportional to the square of time!

Hint; see:

https://www.circuitlab.com/circuit/e32u9c/sinusoidal-sources-01/

for two ways to generate sinusoidal signals signals. One using the CL Signal Sources (Voltage Function Generator or Current Function Generator) the other using the Ideal Source (Voltage or Current) as an arbitrary behavioural source defined by expressions.

See also:

https://www.circuitlab.com/docs/circuit-elements/#behavioralsources

Why is not a sinusoidal function?

2 * Sqr(2) * (WT + PI/4)

The current is:

2*Sqr2 * (Cos PI/4 + JSin PI/4) and the result is

2 + j2

If you build your functions in CL as described in the example, you will see that:

2 * Sqr(2) * (WT + PI/4)

is not a sinusoidal function:

https://www.circuitlab.com/circuit/e6s58c/sinusoidal-and-non-sinusoidal-functions-01/

It is of the form y = mx+c

The result is linearly proportional to time.

Note however that I was wrong about the current being proportional to the square of time. I had (a) assumed by Sqr(2) you meant 2^2 and (b) misplaced it inside the brackets to make 2*(2*WT^2+PI/4)

The solution to:

2*Sqr2 * (Cos PI/4 + JSin PI/4)

is a constant but the result is not: 2 + j2

Assuming by Sqr(2) you actually mean sqrt(2) 2^0.5 then the result is:

-1/sqrt(2)

See:

http://www.wolframalpha.com/input/?i=2Sqrt%282%29+%28Cos+PI%2F4+%2B+jSin+PI%2F4%29

:)