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So if I have a battery connected to a capacitor and then I add a light, where would I put the switch to release the electricity from the capacitor?

Hmmmm, next to the capacitor? ... ;-)

Simulation starts by a diagram, no safety glasses needed.

Just do it and post what you have …

Regards, Sancho

@laser_tag,

What do you want the light to do?

Stay on when you switch it on?

Or turn on then fade out as the charge in the cap decays?

So this is how I though it should go.

https://www.circuitlab.com/circuit/7k5q3q/capacitor-and-light/#postsave_link_and_share

Your link doesn't work. It sends us to:

Error 403: Forbidden

You have not made your circuit unlisted or public. Clicking on your user name:

https://www.circuitlab.com/user/laser_tag/

shows:

laser_tag's Public Circuits: laser_tag has no public circuits.

Please see:

https://www.circuitlab.com/docs/

and in particular:

https://www.circuitlab.com/blog/2012/06/07/unlisted-circuits-easier-sharing-of-schematics/

Sorry about that. Here is the link again. https://www.circuitlab.com/circuit/7k5q3q/capacitor-and-light/

Pardon?

Your switch just shorts out the battery.

It might help you to write down a short specification of exactly what you want to achieve and then try drawing it.

Then post both the spec and the circuit.

See the section on "A design process" in:

https://www.circuitlab.com/forums/support/topic/58b454g6/op-amp-output-different-than-real-world/#comment_2195

All I want to do is add a switch somewhere so when it is closed the light will light up and slowly fade out because of the capacitor.

Thank you.