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| Created | January 01, 2013 |
| Last modified | February 03, 2013 |
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I am new here & I'm trying not to be "thick". I see 9 ground points on this circuit & no output terminals? What am I mis-reading? I'd also think it helpful if the design circuit output current was stated. I understand the Zener function is to prevent the possibility of component failure in the high voltage section resulting in high voltage at the low voltage outputs (wherever they may be). My question is what power rating should the Zener be & what other safety features might be employed, for example MOV or fast blow fuse? |
by peterlonz
January 01, 2013 |
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It might help if you didn't think of this as a production ready circuit. It's merely to illustrate a concept for a different forum (EEWeb). The output terminals are the two load resistors (Rload12 and Rload5). But, one is not always interested in "outputs" when running a simulation. I was more interested in what was going on at the 32VMax point. Regarding the number of ground points, I'm very much a beginner, too -- so my question is, what is the significance of the number of ground points? |
by ReverseEMF
January 02, 2013 |
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Also, notice that this is Circuit is unlisted. The reason this is unlisted and not public is I was only interested in comments regarding my failure to achieve a meaningful simulation. In other words, I would only have made it public if it was a completed design. And, and even other way of putting this is: this offering was framed in an intended context: the context of wanting help with the simulation of an uncompleted circuit -- not the context of inviting critique of the design. |
by ReverseEMF
January 02, 2013 |
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@peterlonz: I took a look at your profile and as of this writing I see one circuit -- a transformerless LED driver that is coincidentally very similar to a circuit presented by someone else at the EEWeb forum I designed my TPS for. Whacky synchronicity! In fact, the circuit on this page is a refinement of that circuit to conform, more, to the specifications given by the forum poster. BTW: your circuit excludes comment, but in case you didn't know, you need at least one ground in your circuit in order for it to simulate correctly. Also, it's clever little circuit -- I learned something from it! At first I thought the 1N4148 diodes would fail, because their PRV is 100V. But I failed to consider that the combination of the series capacitance and the current drawn by the LEDs, will limit the reverse voltage to below 100V. I realized that, after running a Time Domain simulation on your circuit (following the addition of a ground ;) But, I'm wondering why R1 is so low in value. It's purpose is to discharge C1 when power is removed -- not to contribute significant current to drive the LEDs, right? With it at 470Ω, the peak current through the LEDs is 400ma. Did you mean for that to be 470K (more in the range that I would use)? |
by ReverseEMF
January 02, 2013 |
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Replying to those who have offered constructive comment on this circuit: 1) I "borrowed" the circuit, forgot the source so could not give credit. 2) I am very interested in transformerless supplies using an X2 rated capacitor & resistor in combo with a diode bridge. Some circuits are extremely simple but I have yet to understand why some work yet others do not, to drive a range of different LED s say! 3) It took a while to draw this circuit here & add component values (R1 should read 470K). Step 1 in learning! 4) Capacitor C2 should be a polar type with the lower plate at ground potential. Looks like I messed up omitting a clear ground point. 5) I hoped to establish the LED current & potential across the two LEDs by simulation but I really don't understand the input selections at the moment, more experimenting in view of what has been said here. 6) Thanks. |
by peterlonz
January 02, 2013 |
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One reason TPS's don't work (at least in terms of what I assume you mean by "doesn't work") is because the current through the series capacitor is not uniformly bi-directional. In other words, the current through the series capacitor must alternate and be the same in both directions, otherwise the cap will charge more in one direction than the other and thus the balance of the current will be less than required. |
by ReverseEMF
January 11, 2013 |
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