| Created by | |
| Created | June 09, 2012 |
| Last modified | June 10, 2012 |
| Tags | No tags. |
Not provided.
INTEGRADOR DE SEÑAL CUADRADA: Vip(+)=1.5,, Vip(-)=-1V, F=4.3KHz, , AV(4300Hz)=Vop-p/Vip, AV(430Hz)=R2/R1,
Finferior=Fintegrar/10, AV(430Hz)=AV(4300Hz)*(Fint/Finf.),
R2=AV(430Hz)R1=3.6610KOhm=366.6KOhm
Equacion de entrada: Vopp=(Vip/R1C1)*(int)dt, INTEGRAMOS EN MEDIO PERIODO CORRESPONDIENTE A UN CICLO POSITIVO DE LA ONDA CUADRADA.
C1=t /(R1AV(4300Hz))=(1/8600)/(10KOhm3.66)=3.177uF
No comments yet. Be the first!
Please sign in or create an account to comment.
Only the circuit's creator can access stored revision history.