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The following shows the diagram for a sensing and filtering input of a break wire alarm. The logic input is held low by the break wire and goes high once the wire is broken. The triggering voltage for the logic high is around 6V. R2 needs to be very high ( min 1M ) to minimise the current consumption, the R1 makes a low pass filter combined with C1. Once the wire is broken, the voltage on C1 needs to be as high as possible ( over VT+ 6v) to maximise reliability. Considering TVS has 1uA leakage, how would you choose R1 and R2? IC is CD4093BE with Schmitt trigger. https://i.imgsafe.org/6ce38ca7fa.png Kindest regards |
March 13, 2017 |
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I can't see that R1 is doing anything.When there is a break C1 charges through R1 and R2 in series. The 1uA leakage is going to drop 2 volts in R2. If the battery voltage has dropped to say 7 volts this will result in only 5 volts on C1. I think I would go for R2=1M and R2=0. |
March 14, 2017 |
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The R1 is there to make a resistive path from beak wire to logic gate. Please note that the long ( 60ft) wire acts as an antenna so there must be resistance as it's connected to CMOS gate. But as you said R2 should be lower. I think I change both R2 and R1 to 500K. |
March 14, 2017 |
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Understood. |
March 14, 2017 |
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